Monday, 1 July 2013


Statement:-
 The intersection of any two sub-spaces of a vector space is also a subspace of the same vector space.

Proof:-
 Let V be a vector space over the field F and W1 and W2 be its subspaces.

∵                      0єW1 and 0єW2  ⇒ 0єW1∩W2
∴                        W1∩W2≠ф
Let                     a,bєF & α,βє W1∩W2
αє W1∩W2⇒  αєW1 & αєW2
and              βє W1∩W2⇒  βєW1  & βєW2
Hence                W1 is a subspace
a,bєF  and   α,βєW1  ⇒  aα+bβєW1
Also                   W2 is a subspace
a,bєF  & α,βєW2 ⇒  aα+bβєW2
∴               aα+bβєW1 & aα+bβєW2
∵                 a,bєF  and α,βє W1∩W2 ⇒  aα+bβєW1∩W2
Thus W1∩W2 is a vector subspace.

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